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Physics HELP PLS?? A negative charge of -6.0 10-6 C exerts an attractive force of 56 N on a second charge?
A negative charge of -6.0 10-6 C exerts an attractive force of 56 N on a second charge 0.056 m away. What is the magnitude of the second charge? ___C
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- Ossi GLv 79 years agoFavorite Answer
Coulombs law says: the force is
F = k*Q1*Q2/r^2 with k = 9*10^9 Vm/As, r = distance of charges in m.
56 = 9*10^9*6*10^-6*Q2/0.056^2 ->
Q2 = 56*0.056^2/(9*10^9*6*10^-6)
Q2 = + 3.252*10^-6 C <-- ans.
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