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A force of 5.20 102 N exists between a positive charge of 7.80 10-5 C and a negative charge of -3.00 10-5 C. W?
A force of 5.20 102 N exists between a positive charge of 7.80 10-5 C and a negative charge of -3.00 10-5 C. What distance separates the charges?
1 Answer
- 9 years agoFavorite Answer
For this, use the equation:
F = (k*Q_1*Q_2)/r^2
and then rearrange it to be:
r^2 = (k*Q_1*Q_2)/F or r = sqrt[(k*Q_1*Q_2)/F]
r = distance between charges
k = 9E9 N*m^2/C^2
Q_1 = 7.8E-5 C
Q_2 = 3E-5 C
Final answer = .2 meters
Please let me know of any inaccuracies.
Source(s): AP Physics B
