******10 pts****** physics question If you stand on a bathroom scale...?

Use conservation of energy. KE of man at impact = PE in spring at max read.

1) calculste KE at impact

Get t to impact from 1m = gt^2 so t= [2/g]^0.5

Velocity at impact = V = gt = g[2/g]^0.5 = [2g]^0.5

So KE = 0.5 M V^2 = M g where M is mass of man

2) find PE at max reading

spring constant = k = M/0.0006m

KE of spring at max read = 0.5kx^2 = 0.5[M/0.0006][x]^2

3) Now conserve energy

KE=PE

0.5Mg = 0.5[ M/0.0006]x^2

So x^2 = 0.0006g

x= [0.0006g]^0.5

4) find max reading

F= max reading = (x) k =[ M/0.0006][.0006g] = Mg

Hence max reading is 710N{ 9.8 ] = 6958 N

It relies upon on what's meant by ability of "purely earlier the coke bottle leaves her hand". anticipate the size reacts immediately. anticipate the coke bottle is not any longer held, purchase loose to fall. It takes some hundredths of a 2d for it to actual go away her hand after that's released. Bottle is accelerating downward, consequently the stress on (the lady plus coke bottle) is purely too low. The stress of the bathing room scale is barely sufficient to maintain the lady static, no longer the coke bottle. answer - too low.

when you stand on the scale, equate spring force with grav force, -kx = 710N, k=1.18E6

When you jump down, equate spring energy with grav energy, 1/2 kx^2 = mgh = 710N.

x=34.7 mm