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Moles of NaOH? please explain this question?
I have 3 equations:
NaOH(s) -> NaOH (aq)
HCl(aq) + (aq) -> NaCl (aq) + H2O (l) (1.0 m of HCl)
HCl (aq) + (s) -> Nacl (aq) + H2O (l) (0.5 m of HCl)
Calculate the moles of NaOH used in each of the reactions. (Hint: to find number of moles in a solution, multiply the volume in liters by the )
Can someone please explain how to do this?
- by the molar concentration
sorry somehow that got deleted
1 Answer
- 9 years agoFavorite Answer
- The mole to volume conversion is 22.4 So it be 22.4/1 as your last conversion factor in the equations.
Source(s): what I know :)
