Need help with heat transfer chemistry problem?

The heat transfer formula is:

Q=M*S*(deltaT)

joules = mass X specific heat X change in T. T is in Kelvin or C, depending on the units you use for specific heat, which can be j/K or j/C.

If you need to convert to K, it's C+273=K.

Delta T = T(final) - T(initial).

Convert grams to kg for mass.

I see they gave you joules/C. This means you'll have to convert specific heat to C as well, which is normally in K.

Water has a specific heat of 4186j*kg/K

Heat capacity is irrelevant except to help you figure out Q.

Since they tell you T(final) and T(initial), you can figure Delta T -- T(f) = 37C, and T(i) = 82C. Since D(T) = T(f)-T(i), Delta T = 37-82, which is -45. Therefore change in T is 45C, and the reaction is endothermic *(since it's negative). -45C=228K

Your whole equation would be:

Q = m*s*(deltaT) [120g water] + m2*s*(deltaT) [m2=unknown amount water to change T]

Q= .12kg*4186j.kg/K*228K + Xkg*4186j.kg/K*228K

First you have to figure out how much energy was lost, then you can find mass.

.12kg water*4186j/kg = 502.32

Heat capacity 14j/C: You have a Delta T of 45C, therefore 14j/C (45) = 630.

502.32+630 = 1132.32j

This is Q.

Now your whole equation =

1132.32j = .12kg*4186j.kg/K*228K + Xkg*4186j.kg/K*228K

Solve for x, mass (in kg) of water added.

Should be simple!

Hope this helps!

:)

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