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PROBABILITY S1 STATS HELP?

The question literally says

1.)The events A and B are independent and are that P(A)=0.4 AND P( A and B')= 0.3. EVALUATE P(B) and P(A U B)

and another one is

2.)The events A,B are such that P(A)=0.5 AND P(A U B) = 0.7

Find the value of P(B) when

a.) A and B are mutually exclusive

b.) A and B are independent

Another one asks

3.)A fair die is to be thrown ten times. Calculate the probability that:

a.) a score of 6 will be obtained exactly three times

b.) a score of 6 will be obtained for the third time on the tenth throw

Next question is:

4.)Bag A contains 4 red balls and 6 white balls, while bag B contain 3 red balls and 2 white balls. A bag is to be chosen from the outcome of tossing two fair coins; if two heads are tossed than bag A is chosen; otherwise bag B is chosen. From the chosen bag three balls are to be drawn at random without replacement.

a.) Calculate the probability that

i.) 3 red balls will be drawn

ii.) 2 red balls and 1 white ball will be drawn

b.) Given that 2 red balls and 1 white ball were drawn, find the probability that they came from bag A.

Guys, i know that this is alot but I AM LITERALLY BEGGING YOU TO SHOW ME HOW TO DO THIS PLSSSSSSS, if u cannot do all, plssss at least do questions 1 and 2 plssss.

1 Answer

Relevance
  • Anonymous
    9 years ago

    1.

    P(A and B') = P(A) - P(A and B)

    or, 0.3 =0.4 - P(A and B)

    or, P(A and B) = 0.1

    now if A and B are independent then

    P(A and B) = P(A) * P(B)

    or, 0.1 = 0.4 * P(B)

    or, P(B) = 0.25 ......... answer (i)

    now we know the formula,

    P(A U B) = P(A) + P(B) - P(A and B)

    or, P(A U B) = 0.4 + 0.25 - 0.1

    or, P(A U B) = 0.55 ................. answer (ii)

    2. a) when mutually exclusive P(A and B) = 0

    so,

    P(A U B) = P(A) + P(B) - P(A and B)

    or, 0.7 = 0.5 + P(B) - 0

    or, P(B) = 0.2

    b) when independent P(A and B) = P(A)*P(B)

    so,

    P(A U B) = P(A) + P(B) - P(A and B)

    or, P(A U B) = P(A) + P(B) - P(A)*P(B)

    or, 0.7 = 0.5 + P(B) - 0.5*P(B)

    or, 0.2 = 0.5*P(B)

    or, P(B) = 0.4

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