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A force of 0.053 N is required to move a charge of 38 µ a distance of 25 cm in a uniform electric field. What?
A force of 0.053 N is required to move a charge of 38 µ a distance of 25 cm in a uniform electric field. What is the size of the electric potential difference between the two points?
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- jeffreyLv 79 years agoFavorite Answer
… F = Q E = Q | - ΔV / Δx | … --> … ΔV = FΔx / Q …
… ΔV = ( 0.053 N ) ( 25 cm ) / ( 38 μ C )
……… = ( 0.053 N ) ( 25 × 10 ⁻ ² m ) / ( 38 × 10 ⁻ ⁶ C )
……… = 349 V
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