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Please Help with this Probability Question?
Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
I am a little confused on how to work it. My first thought was that it was 3/8, but you would not have the same chance of getting a white marble again on the second draw as you did the first.
Oh, I am sorry, it cut off the end of the question:
Both marbles are white.
3 Answers
- AnakinLv 69 years agoFavorite Answer
If I understand you correctly, the question is:
"Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability that the two marbles selected are white."
In general to find the probability of 2 events occurring, you just multiply the separate probabilities.
First one, P(w): 3 whites, 8 total ===> P(w#1) = 3/8
Second one, P(w): 2 whites, 7 total ===> P(w#2) = 2/7
Total Prob = P(w#1 and w#2) = (3/8) * (2/7) = 6/56 = 3/28 ≈ 10.7%
- Anonymous9 years ago
do you want probability of getting white marbles both times? you have not written about finding pro of getting what?
still,
probability of getting a white on 1st draw = 3/8
& pro of getting white again = 2/7
so,
probability of getting 2 whites in 2 draws = 3/8 * 2/7
= 6 / 56
= 3/28 (appx 10.7%]/
hope it helps.
- 9 years ago
Find the probability that what? That you'll pull out an elephant =0%
that they are marbles? = 100%
specify please
