Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
how to shorten this MySQL query?
SELECT v1.* FROM (
SELECT c1,c2,c3,c4
FROM t1 WHERE left(c1,3)='200'
and c2<>'20' and c3='005' group by c1
) v1 union all
SELECT v1.* FROM (
SELECT c1,c2,c3,c4
FROM t1 WHERE left(c1,3)='200'
and c2<>'20' and c3='006' group by c1
) v1 union all
SELECT v1.* FROM (
SELECT c1,c2,c3,c4
FROM t1 WHERE left(c1,3)='200'
and c2<>'20' and c3='007' group by c1
) v1 union all
SELECT v1.* FROM (
SELECT c1,c2,c3,c4
FROM t1 WHERE left(c1,3)='200'
and c2<>'20' and c3='008' group by c1
) v1;
Sorry, forgot to add. The queries are all the same except for "c3" value. Let's assume that c3 = room number. My objective is to create a single query with all different c3 value inside it. How ah?
1 Answer
- 9 years agoFavorite Answer
try it. what say you ?
SELECT * FROM t1
WHERE LEFT(c1,3)='200'
AND c2<>'20'
AND c3 IN (SELECT roomcode FROM roomlist)
GROUP BY c1;
EDIT:
do not use roomcode so that it will list all room. do not bother to use other table, hiiiyaaaa
SELECT COUNT(*),outletcode FROM t1 WHERE LEFT(c1,3)='200'
AND c2<>'20' GROUP BY outletcode