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For a tire whose diameter is 22.5 inches and is traveling at 66.1 miles per hour, how many revolutions per min?
For a tire whose diameter is 22.5 inches and is traveling at 66.1 miles per hour, how many revolutions does the tire make per minute?
6 Answers
- ranjankarLv 79 years agoFavorite Answer
66.1 mph
66.1/60 = 1.1016666 miles per minute = 69801.595 inches per minute
circumference = 3.142 X 22.5 = 70.695 "
no of revolutions = 69801.595 /70.695 = 987.36254 revolutions
ANSWER 987
- listen to meLv 49 years ago
circumference = pi*d
22/7*22.5 = 70.65 inches
66.1 miles per hour = 66360 inches an hour
66360/60 =1106 inches in a minute
so the number of revolutions per minute = 1106/70.65 = 15.65
close to 15 and a half revolutions
- RameshwarLv 79 years ago
CIRCUMFERENCE OF TIRE = 22.5 X 3.142 = 70.714 INCHES [ circumference = 2pi r]
revolution = 66.1x1760x3x12/ 70,714 per hr = 4188096/70.714 /hr
= 59225.8/ hr
=59225.8./60 per minute
=987 /min. ANSWER
[ NOTE --- 1 mile= 1760 yards
1 yard = 3 feet
1 feet= 12 inches ]
- PranilLv 79 years ago
circumference = 2πr = π d
= 22.5 × 3.14 = 70.65 inch
circumference = 1 revolution
distance travelled in 1 minute = 66.1/60 = 1.102 miles per minute
1.102 miles = 1.102 × 5280 feet = 1.102 × 5280 × 12 inch
so revolution per minute = distance/circumference
= 1.102 × 5280 × 12/70.65 = 987.992 ≈ 988
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- Anonymous9 years ago
does the diameter matter? if its traveling 66.1 mph wouldnt it be the same regardless?
- filonukLv 45 years ago
How the fack might want to i understand? i wager not, they could want their passengers to all starve to demise like all reliable delivery provider. yet they ought to positioned the radio on! I <3 track! ((d[2c6b3be4d5c612986c9bf076e648992c6b3be4d5c612986c9bf076e648992c6b3be4d5c612986c9bf076e64899]b))