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Yang jago matematika tolongin dong?
1. lim x->4 {(ax+b-akar x)/x-4} = 3/4 maka a+b
2. lim x->0 4x/x+sin 3x
3 Answers
- Anonymous9 years agoFavorite Answer
(2).
k = lim 4x/(x + sin 3x)
x → 0
k = lim 4/(1 + 3 cos 3x)
x → 0
k = lim 4/(1 + 3)
k = 1
- man0eul3rLv 49 years ago
1. lim....ax+b- √x ......3
x → ₄ -------------- = -----
................x - 4............4
krn penyebut nya ( x - 4 ) dan nilai x mendekati 4 , agar punya limit bentuknya harus bentuk tak tentu 0/0 jadi
ax + b - √x = 0
4a + b - √4 = 0
4a + b - 2 = 0
4a + b = 2 ...............(i)
biar mudah, pake aturan hopital, turunkan pembilang & penyebut 1 kali
a -1/(2√x)......3
-------------- = ---
......1..............4
a -1/(2√4).....3
------------- = ---
......1.............4
a -1/4 = 3/4
a = 1 , kemudian substitusikan ke (i)
b = -2
a + b = 1 + (-2) = -1
- 9 years ago
2. lim x->0 4x/x+sin 3x
kalo lim x->0 buat sin 3x
cara cepetnya sin sama x nya langsung dicoret
jadi 4x/x + 3 = 7
