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Abel asked in Science & MathematicsPhysics · 9 years ago

physics question help help not sure?

A 55 kg box with initial velocity of 0.45 ms−1 slides down a ramp inclined at an angle of 23° with the horizontal. If the coefficient of friction between the box and the ramp is 0.24, how fast will the box move after it travelled 2.1 m down the ramp?

please explain step by step how to solve. thx

1 Answer

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  • ?
    Lv 7
    9 years ago
    Favorite Answer

    Do U have a pencil handy :>)

    1) First sketch the ramp and box.

    2) Calculate the weight (mg) of box and show it as a vector on UR sketch.

    3) Sketch two components of weight vector, parallel and perpendicular to ramp

    4) Mathematically compute using sin & cos, the sizes of these components

    5) The perpendicular component = Normal force, from it compute: µk(N) = (0.24N) = fk

    6) Sketch the kinetic friction force (fk) vector {size computed in 5)} on UR diagram

    7) Compute {see UR diagram} the NET FORCE (Fnet) that acts down ramp.

    {Fnet = weight component parallel to ramp - fk}

    8) Compute the NET ACCELERATION that acts down the ramp = a = Fnet/m {m = 55}

    9) Use kinematic relationship: (Vf)² = (Vi)² - 2ad {Vi = 0.45, "a" from 8), d = 2.1}

    solve 9) for Vf = ANS

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