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help with thermal please (soda drinking)?

Before going in for an annual physical, a 70.0 kg person whose body temperature is 37.0 degrees Celsius consumes an entire 0.355 liter can of a soft drink (which is mostly water) at 12.0 degrees Celsius. What will be the person's body temperature T_final after equilibrium is attained? Ignore any heating by the person's metabolism. The specific heat capacity of a human body is 3480 J/kg \K?

I did the whole mcdeltaT=mcdeltaT and i keep getting the answer wrong. Can I get some help?

mass of the soda is .355 kg and should be treated as water so c=4180.

2 Answers

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  • Whome
    Lv 7
    9 years ago
    Favorite Answer

    Let t be the equilibrium temperature

    m1c1ΔT1=m2c2ΔT2

    0.355(4180)(t - 12) = 70(3480)(37 - t)

    1483.9t - 17806.8 = 9013200 - 243600t

    245083.9t = 9031006.8

    t = 9031006.8 / 245083.9

    t = 36.8°

  • Anonymous
    5 years ago

    It really depends on how much you plan on drinking. Plan A is $34.50. If for instance, you don't drink very much then plan A is better. Say you drink 2 times a day. That leaves you 6 tickets. If you drink 3 times a day, you're short 1 ticket. It also gets you into the dance party with the DJ plus pizza and drinks. Plan B will cost you approximately $50.31 (per day + tax/gratuity) with unlimited drinks and you get a thermal cup that can be refilled multiple times. I would check and see if you can get into the dance party without purchasing the Plan A. If not, and you really want to attend the party, then go with Plan A. For complete explanation about the meals and drink plans check out NCL's website.

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