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For each m with 6 ≤ m ≤ 13, how many zero divisors does Z/mZ have?

Please, can I get help for this problem?

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  • 9 years ago
    Favorite Answer

    An element, [a] will either be a unit or a zero divisor, so check to see if (a,m)=1. If so then, this is a unit and not a zero divisor. If 1< gcd(a,m)<m, then [a] is a zero divisor. For example Z/12Z has 7 zero divisors:

    (1,12) is not because (1,12)=1 making it a unit

    (2,12) has a gcd less than 12 and therefore satisfies 1<(2,12)<m, so it's a zero divisor

    (3,12) zero divisor

    (4,12) zero divisor

    (5,12)=1 so not a zero divisor

    (6,12) zero divisor

    (7,12) not zero divisor

    (8,12) zero divisor

    (9,12) zero divisor

    (10,12) zero divisor

    (11,12)not zero divisor

    (12,12) not zero divisor

    Source(s): I'm in abstract algebra
  • ?
    Lv 4
    4 years ago

    in case you seem on the derivation of the calculus with the aid of Leibniz you will locate the comparable element. a nil divisor. da/d0 no longer evidence of the divine yet larger arithmetic factors to infinity in lots of cases. in actuality in M-concept the difficulty of infinity stoning up in each single place is protecting decrease back progression interior the sector. interestingly that God used Infinity as his development blocks to construct the Universe.

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