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John
John asked in Science & MathematicsPhysics · 9 years ago

Need physics help please as soon a possible?

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Three small lamps, R1 = 4.5 , R2 = 3.7 , and R3 = 1.6 are connected to a 9.0 V battery, as shown below.( the link above)

(a) What is the equivalent resistance of the circuit?

______ohms

(b) What is the current in the battery?

________A

(c) What is the current in each bulb?

I1 =______ A

I2 = _____ A

I3 = _______A

(d) What is the potential difference across each bulb?

V1 = _____ V

V2 = _____ V

V3 = ______ V

PLease show equations used

1 Answer

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  • pierrot bules
    Lv 7
    9 years ago
    Favorite Answer

    a) Req = R1 + R2 * R3 / (R2 + R3) = 4.5 + 3.7 * 1.6 / 5.3 =4.5 + 1.11698 = 5.617Ω

    b ) current in the battery = 9 / Req = 9 / 5.617 = 1.602 A

    c) current in each bulb

    I1 = 1.602 A ( R1 )

    I2 = V2 / R2 = 1.791 / 3.7 = 0.484 A

    I3 = V3 / R3 = 1.791 / 1.6 = 1.119 A

    d) V1 = 4.5 * 1.602 = 7.209 V

    V2 = V3 = 9 - 7.209 = 1.791 V

    Goodbye

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