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Direct Proportion Question I need help please :(?
The cube of y is directly proportional to x(x-1). Given that y=3 when x=3, Find
(a) an equation connecting x and y
(b) y^3 when x = 5
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- βαяяϵdθLv 79 years agoFavorite Answer
y ^3 = k*(x)(x-1)
3^3 = k*(3)(3-1)
3^2 = k*(2)
2k = 9
k = 9/2
a)
y^3 = 9/2*(x)(x-1)
y^3 = 9/2*(x^2 -x) . . .ans.
b)
y^3 = 9/2 *(x)(x-1)
Y^3 = 9/2*(5)(5-1)
y^3 = 9/2*(5)(4)
y^3 = 9*(5)(2)
y^3 = 90 . . .ans
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