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C code; pass by value, reference and value-result?
void swap(int list[], int i, int j) {
int temp= list[i];
list[i]= list[j];
list[j] =temp;
}
int main(void) {
int x[3] ={5, 2, 4};
swap(x, 1, 2);
}
What is the final value of the array x for each of the following parameter passmg assumptions?
(a) Argument xis passed by value.
(b) Argument x is passed by reference.
2 Answers
- ?Lv 79 years agoFavorite Answer
Sorry if you take definition of the pass by value valid here, then array is not supposed to change.
However, in fact in C language array names are pointers to the addresses. When we are sending arrays to a function means, we are really sending their addresses only. There is no concept of reference variables in C language
