How do you find the final velocity when only given time?

We will also assume that she had no initial velocity (i.e. she was just dropped, not thrown).

Vf = (9.8 m/s^2)(2.6 s) = 25.48 m/s

d = (1/2)(9.8 m/s^2)(2.6 s)^2 = 33.124 m

But see, you don't have "only...time" You also have g = 9.8 m/s^2 [NOTE NOT m/s as you give it.]

So think about the physics. What happens to your speed when you accelerate A the car for some time T. It gets faster the longer the car accelerates.

And that's the same when falling. Sally gets faster because she's accelerating at g = 9.8 m/s^2 for every second T she falls. And in math talk that's V = U + gT; where U is whatever initial speed Sally was at when she started to fall. We assume U = 0.

So there you are. Simple physics. Bodies get faster the longer they accelerate or for a falling body starting with U = 0, that's V = gT. You have T = 2.5 seconds and g = 9.8 m/s^2.

Go do it.

The distance traveled in that 2.5 seconds is distance = average speed X time of falling. In math that's S = Vavg T. Assuming U = 0, Vavg = V/2 = gT/2. So S = Vavg T = gT/2 * T = 1/2 gT^2. Again you have g and T.

Go do it some more.

you mean acceleration due to gravity is 9.8 m/s^2. So..... I find it easier to graph an equation like this. Make a graph, with the velocity being the y-axis, and time being the x-axis. Given that the accel is 9.8 (the slope is 9.8), that means that acceleration is velocity over time, which states that acceleration is nothing more than change in velocity over time. so, to find the final velocity, just know that V/2.6=9.8.....so just multiply by 2.6 on both sides to find V, or final velocity. V=25.5 m/s... to find displacement, just use the thing you would use to find the area of a polygon. Since it's accelerating, it's going to have a slope, therefore it's shaped like a triangle. 1/2 X BH. so.... you know that velocity or height is 25.5 m/s, and that time is 2.5 seconds. To find displacement just do "1/2(25.5)(2.5)= 31.85 m". So, are you mad?

It's not a perfectly worded question.

But I'd assume that the initial velocity is zero. So you've got initial velocity, time and acceleration. Which will allow oyu to calculate the final velocity, and the distance traveled.

Velocity = (9.8 x 2.6) = 25.48m/sec.

Distance = (v^2/2g) = 33.124 metres.

You were given 2 things, that's all you need.