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Chemical Equilibrium question!! Please help!!!!?
Assume you have 4.00mol of synthesis gas with a 3:1 mol ratio of H2 (g) to CO(g) in a 15.0L flask. What will be the mole fraction of CH4(g) at equilibrium at 1000K ?
CO(g) + 3H2 (g) <-> CH4(g) + H2O (g)
Kc= 190 at 1000K
delta H= -230 kJ
Please help!! Thank you very much!
1 Answer
- 9 years agoFavorite Answer
CO + 3H2 <---> CH4 + H2O
4 mol/ 15 l 4 mol/15 l 0 0
-x -3x x x
190 = x^2 /(4/15 - 3x)^3 * (4/15 - x)
solve for x
once u solved for x that will be your concentration of CH4
convert concentration to moles
then plug x back into all of the concentrations
and find the moles of each gas
then add up your total number of moles
mole fraction of ch4 = moles of ch4 / total moles in substance
