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Termodinamika mohon segera dijawab?
Sejumlah gas ideal mula-mula bertekanan 10 atm dan suhunya 127OC dalam wadah yang tetap. Jika 2/5 bagian massa gas keluar ternyata suhunya tinggal 27OC maka berapakah tekanannya sekarang?
*Thanks*
1 Answer
- CingcangkelingLv 79 years agoFavorite Answer
P1 = 10 atm......P2 = __ ?
T1 = 400 K........T2 = 300 K
m1 = m.............m2 = (1 - 2/5)m = 3/5 m
V1 = V2
PV = nRT = (m/Mr) RT
Perbandingan nilai untuk dua keadaan:
P2 V2......m2/Mr R T2
---------- = -------------------......coret V, Mr, R
P1 V1......m1/Mr R T1
.....P2.....3/5 m...300
....----- =.----------..-------
.....10....... m......400
.....P2.....3...300
....----- =.---..-------
.....10.....5...400
.....P2.....9
....----- =.-----
.....10.....20
.....P2 = 90/20 = 4,5 atm..<-- jawaban
Tekanan gas sekarang menjadi 4,5 atm
Ok ?