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Termodinamika mohon segera dijawab?

Sejumlah gas ideal mula-mula bertekanan 10 atm dan suhunya 127OC dalam wadah yang tetap. Jika 2/5 bagian massa gas keluar ternyata suhunya tinggal 27OC maka berapakah tekanannya sekarang?

*Thanks*

1 Answer

Rating
  • 9 years ago
    Favorite Answer

    P1 = 10 atm......P2 = __ ?

    T1 = 400 K........T2 = 300 K

    m1 = m.............m2 = (1 - 2/5)m = 3/5 m

    V1 = V2

    PV = nRT = (m/Mr) RT

    Perbandingan nilai untuk dua keadaan:

    P2 V2......m2/Mr R T2

    ---------- = -------------------......coret V, Mr, R

    P1 V1......m1/Mr R T1

    .....P2.....3/5 m...300

    ....----- =.----------..-------

    .....10....... m......400

    .....P2.....3...300

    ....----- =.---..-------

    .....10.....5...400

    .....P2.....9

    ....----- =.-----

    .....10.....20

    .....P2 = 90/20 = 4,5 atm..<-- jawaban

    Tekanan gas sekarang menjadi 4,5 atm

    Ok ?

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