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3, 6, 11, 18,... The first four terms of a sequence are shown above. Which of the following could be the ?

3, 6, 11, 18,... The first four terms of a sequence are shown above. Which of the following could be the formula that gives n th term of this sequence for all the positive integers n?

A) 2n

B) 2n + 1

C) 3n

D) n2 ( n to the 2nd power) + 1

E) n2 (2nd power) + 2

this is too much for me and I need help does anyone know this?? And how they got the answer??

3 Answers

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  • 9 years ago
    Favorite Answer

    The choice is E

    1^2 + 2 = 1 + 2 = 3

    2^2 + 2 = 4 + 2 = 6

    3^2 + 2 = 9 + 2 = 11

    4^2 + 2 = 16 + 2 = 18

    Source(s): Math teacher
  • Anonymous
    9 years ago

    It would be 'B'

    -from 3 to 6 the difference is 3. if 3 is the first term that makes n=1 so 2*1+1=3

    -from 6 to 11 the difference is 5. if 6 is the second term that makes n=2 so 2*2+1=5

    -from 11 to 18 the difference is 7. if 11 is the third term that makes n=3 so 2*3+1=7

    -etc. etc.

    Are you taking Calc 2? doing Series and Sequences

    Source(s): Math Tutor
  • lucey
    Lv 4
    4 years ago

    easyyyy dont hassle the version is +3, +5, + 7 and that all of them have diff of +2 it turns into n squared so n^2 as there are 2 steps to it after which you have +2 as that's the consistent replace so it particularly is n^2 + 2 examine it out to work out if it works

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