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Reading the Standard Reduction Table?
For
Cu(2+) + 2e(-) --> Cu E=+0.34V
Does this mean the reaction requires 0.34V of energy to occur?
1 Answer
- 9 years agoFavorite Answer
This is only half of a reaction--the reduction half. You would need an oxidation half-reaction to have a complete chemical reaction.
To write an oxidation half-reaction, choose another half-reaction from the standard reduction table. Now, write it in the reverse direction. Also, change the sign of the potential (E).
Say we use chlorine for the oxidation:
2Cl(-) --> Cl2(g) + 2e(-) E=-1.36V
To come up with a chemical reaction, add the two half-reactions. Make sure the number of electrons cancel. And the cell potential would just be the sum of the two Es.
Cu(2+) + 2Cl(-) --> Cu + Cl2(g) E=+0.34V-1.36V=-1.02V
The 0.34V is the amount of energy that this half-reaction uses or produces relative to the hydrogen half-reaction: 2H(+) + 2e(-) --> H2(g) E=0V