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calculate the heat change in calories when 65.3g of steam at 100 degrees C condenses to water at the same temp?

Thermochemistry help please :)

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  • 9 years ago
    Favorite Answer

    Latent heat of condensation of water is 540 c/g.

    So the steam has to give up 65.3*540 calories to condense to water at 100C from steam at 100C.

    = 35,262 calories.

  • 5 years ago

    you want to calculate the ability it takes for the section replace from H2O(g) -> H2O(l) to ensue that is merely (moles)x(KJ/mol ingredient) then you do commonly used thermodynamic calculations for H2O(l) going from 100C to 0C and then you want to calculate the ability it takes for the section replace H2O(l) -> H2O(s) to ensue that is an same variety of equation as in the previous yet with a sparkling fee for the (KJ/mol) ingredient.

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