Calculate the mass of sulfate in your sample of alum based on mass of BaSO4?

I'll take it that the 1.52 refers to 1.52 grams of BaSO4 ??

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http://www.ausetute.com.au/percentc.html

To determine the amount of sulfate, compare the mass of sulfate (SO4) within the barium sulfate (BaSO4). Then ratio down, allowing for the fact you only have 1.52 grams. You'll need to refer to a periodic table.

Formula mass of BaSO4 = 137.3 + 32.1 + 4(16) = 233.4

mass of (SO4) = 32.1 + 4(16) = 96.1

Using ratios:

mass (SO4) / mass (BaSO4) = X / 1.52

X = 0.63 grams

Now Alum in hydrated form has the formula, KAl(SO4)2·12H2O

In anhydrous form its formula is KAl(SO4)

Formula mass (hydrated alum) = 39 + 27 + 2(96.1) + 12(18) = 66 +192.2 + 216 = 474.2

formula mass (anhydrous alum) = 258.2

mass of (SO4) in alum = 192.2

Hence

% sulfate in hydrated alum = 192.2 / 474.2 x 100 = 41 %

% sulfate in anhydrous alum = 192.2 / 258.2 x 100 = 74.4 %

Hope this helps.

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