Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
What is [Pb] in a saturated solution that has [I] = 2.3*10^-4?
A particular saturated solution of PbI2 has [Pb] = 5.0*10^-3 and [I] = 1.3*10^-3
1 Answer
- CazleyLv 59 years agoFavorite Answer
PbI2 -------> Pb^2+ + 2 I^- and Ksp = [Pb^2+][^I-]^2
Use the data from the "particular saturated solution" to solve for Ksp.
Ksp = (5.0 x 10^-3) (1.3 x 10^-3)^2 = 8.45 x 10^-9
I'll keep the extra significant digit for now.
Now you use this value and solve for the lead concentration you need.
8.45 x 10^-9 = [Pb^2+] [ I^-]^2 = x (2.3 x 10^-4)^2
x = [Pb^2+] = .16 M
