Calculate the average current used in the electrolysis.?

i just dont know where i am getting wrong ....maybe the online answer sheet you are using is very sensitive with significant figures ...

here is the solution for this question ....

atomic mass of Palladium = 106.4 g/mole

so no.of moles of Pd = 0.1064/106.4 = 0.001

electrode reaction :

Pd2+ + 2e- -----> Pd

for 1 mole of deposition of Pd ...electricity recquired = 2 F = 2 X 96500 C

so for 0.001 mole deposition of Pd ....electricity recquired = 2 X 96500 X 0.001 = 193 C

as Q = I X t

so I = Q/t = 193/27.4 = 7.044 Ampere

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RE :Calculate the average current used in the electrolysis.?

an aqueous solution of pdcl2 is electrolyzed for 27.4 seconds during this time 0.1064 g of Pd is deposited on the cathode. Calculate the average current used in the electrolysis.

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