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Given the following quadratic equation, find;?
a. the vertex
b. the axis of symmetry
c. the intercepts
d. the domain
e. the range
f. the interval where the function is increasing, and
g. the interval where the function is decreasing
h. Graph the function.
y=x^2+6x+5
please show the steps. I really need help on it!
1 Answer
- Anonymous9 years ago
a. knowing that quadratic equations are written out in the general form ax^2 +bx+c, and that the x-coordinate of the vertex can be found by the formula -b/2a, the x-coordinate of the vertex is -3. Plugging in -3 for x into the original equation leads to the y coordinate, which in this case is -4. Vertex is at (-3,-4)
b. x=-3
c. To find y intercept, set x=0. This leaves a y-intecrept of 5. To find x intercept, set y=0, and factor equation. This leads to 0=(x+5)(x+1). This leaves intercepts of x=-5 and -1.
d. All real numbers
e. y>= -4
f.x>-3
g. x<-3