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Use integration to find the area of the region outside the circle r=1/2 and inside the circle of r=cos(theta)?
All I've got so far is this.
1/2=cos(theta)
so...
theta=1.047 or pi/3
2 Answers
Relevance
- Anonymous9 years ago
1/2 = cosθ
θ = -π/3, and π/3
A = (1/2) ∫ (cosθ)² - (1/2)² dθ, θ= -π/3 to π/3
A = √(3)/8 + π/12
- ?Lv 44 years ago
the equasion of a circule is x^2 + y^2 = r^2 so your formulation is x^2 + y^2 = (one million/2)^2 you are going to be waiting to intergrate that if it relatively is your homework. it is going to be in a table some place....
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