Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

? asked in Science & MathematicsChemistry · 9 years ago

Can someone please explain the difference between reducing and non-reducing sugars?

Why do you need an anomeric carbon? I don't understand why that's necessary...can't any of the other hydroxyl groups of the sugar get oxidized?

2 Answers

Relevance
  • DrBob1
    Lv 7
    9 years ago
    Favorite Answer

    The anomeric OH group isn't an alcohol, it is a hemiacetal. This makes it MUCH easier to oxidize than a regular alcohol group. Thus, the other OH groups are unreactive.

  • 5 years ago

    Change between reducing Sugar and Non-reducing sugar is in its constitution. Lowering sugars have a aldehyde crew or carbonyl functional crew, which can also be diminished to -OH workforce by chemical reaction. Some sugars like Fructose get re-organized in special conditions like alkaline pH, and type a compound that is reducible. Most common reducing retailers to decide this nature are Tollen's reagent, Fehling's reagent, Benedict's reagent, and many others. Maltose has an aldehyde group in them, and for this reason it's a lowering sugar. Non-decreasing sugars do not minimize the above considering of absence of an aldehyde crew. (E.G. Sucrose) Fructose does no longer have an aldehyde crew, yet it's lowering, because it will get rearranged to the decreasing glucose in normal solution.

Still have questions? Get your answers by asking now.