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test for divisibility by 27 ?
how to check whether a number is divisible by 27 ?????
example:- 36 is not divisible by 27
but (3+6) = 9 is divisible by both 3 and 9...
i think the best test is
Subtracting 8 times the last digit from the rest.
4 Answers
- 9 years agoFavorite Answer
Sum the digits in blocks of three from right to left. If the result is divisible by 27, then the number is divisible by 27.
Subtract 8 times the last digit from the rest.
A test for divisibility by 27 would be:
- check for divisibility by 3
- divide by 3
- check for divisibility by 9
Source(s): Read here - http://en.wikipedia.org/wiki/Divisibility_rule#Bey... http://www.vbforums.com/showthread.php?257144-Divi... - δοτζοLv 79 years ago
Just perform the long division, or divide it by 3 then check for divisibility of 9. If that's too much work, here's a pdf I found on google that gives divisibility tests for 2 - 102.
- 9 years ago
if the number is divisible is divisible by 3 and 9 its obviously divisible by 27
for checking divisibilty by 3 add the digits like 135 => 1+3+5=9 which is divisible by 9 and it is also divisible by 3
for 9 addition must be higher than 3,6 and must be multiple of 9
