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I need help. Did I do this right?

I had the equation l2x-5/3l = 7

2x-5/3 = 7

2x-5/3*3 = 7*3 --> 2x-5 = 21

2x-5+5 = 21+5 --> 2x = 26

2x/2 = 26/2 --> x = 13

2x-5/3 = -7

2x-5/3*3 = -7*3 --> 2x-5 = -21

2x-5+5 = -21+5 --> 2x = -16

2x/2 = -16/2 --> x = -8

I keep getting where the -8 doesn't fit when you plug it back into the original equation l2x-5/3l = 7. Am I doing my math wrong or is there really No Solution?

Update:

When I multiply by 3 I'm using the Multiplication Rule of Equality. I don't distribute.

Update 2:

Matt, THANK YOU SO MUCH. I'd pick yours as Best Answer, but it won't let me right now... Later.

-16 -5... Man, I was adding there. Explains so much.

7 Answers

Relevance
  • Matt
    Lv 7
    9 years ago
    Favorite Answer

    I'm assuming you meant |(2x-5)/3| = 7; make sure to use parentheses when necessary.

    In that case, x = -8 does work in the original equation:

    |(2x - 5) / 3| = 7

    |(2 * -8 - 5) / 3| = 7

    |(-16 - 5) / 3| = 7

    |-21 / 3| = 7

    |-7| = 7

    7 = 7

    Hope that helps! :)

  • ?
    Lv 5
    9 years ago

    You forgot to distribute when you multiply by 3

    2x-5/3*3 = 7*3 --> 6x-5 = 21

    then you should get the right answers which happen to be:

    x= -8/3 and x =13/3

  • ?
    Lv 7
    9 years ago

    2x-5/3 = 21/3

    2x = 26/3

    x = 13/3

    2x-5/3 = -21/3

    2x = -16/3

    x = -8/3

    Answer x = 13/3 and -8/3

  • 9 years ago

    |2x-5/3| = 7

    |-6x+5| = 21

    So you have 6x = 26

    and -6x = 16.

    Solutions would be...

    x = -8/3

    and

    x = 13/3

    Source(s): yeah adding in parenthesis changes everything, we aren't psychic ya know...
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  • Annie
    Lv 4
    9 years ago

    in your first line where you multiply by 3 you need to multiply the 2x by 3 as well which will make it 6x

  • 9 years ago

    your mistake in linge 2 , you should multiply 2x by 3 as well

  • 9 years ago

    absolute value is positive. it is a distance .

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