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tolong dong fisika tentang taraf intensitas bunyi!!!?
Berapa persen daya bunyi yang harus diserap oleh alat peredam suara yang diletakkan pada dinding sebuah ruangan agar kebisingan suara berkurang dari 90 dB menjadi 70 dB? tolong yaaa makasih
1 Answer
- CingcangkelingLv 79 years agoFavorite Answer
TI = 10 log (I/I₀)
Untuk TI₁ = 90 dB
.90 = 10 log (I₁/I₀)
...9 = log (I₁/I₀)
I₁/I₀ = 10⁹
...I₁ = 10⁹ I₀
P₁ = I₁ A = 10⁹ I₀ A
Untuk TI₂ = 70 dB
.70 = 10 log (I₂/I₀)
...7 = log (I₂/I₀)
I₂/I₀ = 10⁷
...I₂ = 10⁷ I₀
P₂ = I₂ A = 10⁷ I₀ A
∆P......10⁹ I₀ A - 10⁷ I₀ A
---- = ----------------------- × 100%
P₁...............10⁹ I₀ A
∆P......(10⁹ - 10⁷) I₀ A
---- = --------------------- × 100%
P₁...............10⁹ I₀ A
∆P......0,99×10⁹
---- = ------------- × 100% = 99 %..<-- jawaban
P₁..........10⁹
Ok ?
