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help again with coin problem?
A sum of money amounts to twenty dollars consisting of nickels, dimes and quarters. There are
10 times as many dimes as there are quarters and the number of nickels
exceed TWICE the number of dimes and quarters by 24.
Find the number of coins of each denomination
this is a corrected version twice was omitted
1 Answer
- curtisports2Lv 79 years agoFavorite Answer
It's been too many years away from working with algebra to give you the algebraic formula, but I came up with the answer using logic and basic math skills in under a minute:
8 quarters = $2
80 dimes = $8
88*2 = 176
176 + 24 = 200
200 nickels = $10
$2 + $8 + $10 = $20
