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Determine the Concavity -- Answer in 20 and get best answer!?
Determine the concavity of the function:
f(x) = 2x^3 - 9x^4 - 108x
Thanks! Answer within twenty minutes and get a best answer!
1 Answer
- 9 years agoFavorite Answer
Take the first and second derivatives
f'(x) = 6x^2 - 36x^3 - 108
f''(x) = 12x -108x^2 = 12x(1-9x)
f''(x) is 0 when x=0 and x=1/9. When x is less than 0, f''(x) is negative. When x is between 0 and 1/9 f''(x) is positive and when x is greater than 1/9, f''(x) is negative.
The concavity test tells us that when f''(x) is positive, the function is concave up. When f''(x) is negative, the function is concave down.
Therefore, f is concave up on (0,1/9) and concave down everywhere else.