Need help with an Assembly (x86) program?

declare PrintOut Function first with one integer parameter to print out them on the screen.

then call that function like this :

======================

mov esi,1

Loop:

push esi

call PrintOut

inc esi

cmp esi,10

jle Loop

//put ur next code here...

You create a string that consists of 3 characters (= 3 bytes). The ascii character '1', then '0' and then a 0 byte for termination.

I don't know what assembler you are using so I don't know what syntax your assembler supports. But it's probably something like this.

db 49,48,0

or if your assembler supports characters you may be able to write

db '1', '0', 0

Then you just increase the value of the second byte in a loop and print out the string using the address of the second byte. At the end of your program you print out the string again but this time use the address of the first byte.

But that's not really the shortest one. The shortest possible way to write it is to define a string like this

db '1', 10, '2', 10, '3', 10, '4', 10, '5', 10, '6', 10, '7', 10, '8', 10, '9', 10, '1', 10, '1', '0', 0

and then print that string