Urgent! Help on Physics?

1. Beat frequency is just the difference in the frequencies of the two wires. 6 beats/s means that the tension increased the frequency of one to 606 Hz. The equation for tension/frequency is:

f1/f2 = sqrt( T1/T2)

So you have:

606/600 = sqrt(T1/T2)

1.01=sqrt (T1/T2)

T1/T2 = 1.0201

Or a 2.01% increase in tension.

2. This is a doppler effect problem. Again, the beat frequency is the difference in frequencies, so we must find the frequency of the reflected waves first. The doppler effect equation is:

f1 = f2 + (2)(v1)(f2)/v2

frequency reflected = f1

frequency of source = f2 = 28,000 Hz

velocity of object = v1 = 0.95 m/s

velocity of sound = v2 = 340 m/s

Rearranging gives:

f1-f2 = (2)(v1)(f2)/v2

f1-f2 is what we want. (the beat frequency)

f1-f2 = (2)(0.95)(28000)/340 = 156.47 Hz.

So the beat frequency is 156.47 Hz.

This concern is particularly complicated me as nicely.what's the question? i'm able to in ordinary terms wager that the question is: at what attitude is the rope related to the field. is this the question? if so, answer as follows: via fact the field strikes at a relentless velocity, the consequent or internet tension is 0. consequently the utilized tension in a horizontal path could be equivalent to the friction tension: utilized tension horizontal path = 25N 25N is the horizontal component to a 43N tension at an attitude ? with the floor. sparkling up for ?. cos ? = 25/40 3 cos ? = 0.5814 ? = fifty 4.40 5° above the horizontal The rope became at an attitude of fifty 4.40 5° above the horizontal