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Is this correct reaction of Ni and Cu with NHO3?
Ni(s) + Cu(s) + HNO3 --> Cu(+2) + Ni(+2) + 4NO3(-) + 4H2O + 4NO2
The reason I wrote it up in this way, is because I have a nickel cobber alloy that I am dissolving in the nitric acid.
Afterwards I am analyzing the solution to determining how much cobber and nickel there was in the alloy. That's why I made it as one reaction, and why I would prefer to show Cu+2 and Ni+2 by themselves on the product side.
1 Answer
- kumorifoxLv 79 years agoFavorite Answer
You have two reactions occurring, one of nickel and one of copper. Treat them separately. Also, do not mix ionic and molecular equations. Keep consistent in using ions or using complete formulae. Finally, you have to balance the equation.
Ni(s) + 4HNO3(aq) → Ni(NO3)2(aq) + 2NO2(g) + 2H2O(l)
Cu(s) + 4HNO3(aq) → Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)