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I need help on my Algerbra problem! He problem is 7a^2b^9c • 14a^7b^4c. ^ = to the power of.?
I don't even know how to work this problem. Need to know by tommorow! THANKS to my helpers!
2 Answers
- Marley KLv 79 years agoFavorite Answer
it's all multiplication, so take it piece by piece.
multiply the constants: 14x7 = 98
multiply the a's: a^7 x a^2 = a^9
multiply the b's: b^4 x b^9 = b^13
multiply the c's: c x c = c^2
final answer: 98 a^9 b^13 c^2
(notice that when you multiply variables with the same base, you ADD THE EXPONENTS)
that's it! ;)
- 9 years ago
7a^2b^9c* 14a^7b^4c= 98 a^9b^13c^2
7*14= 98 when you multiply you add exponents 2+7=9 9+4=13 1+1=2
