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At a certain temperature, the pH of a neutral solution is 7.49. What is the value of Kw at that temperature?
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- HPVLv 79 years agoFavorite Answer
[H3O+] = 10^-pH = 10^-7.49 = 3.2 x 10^-8 M
Since [H3O+] = [OH-] in pure water, [OH-] = 3.2 x 10^-8 M
Kw = [H3O+][OH-] = (3.2 x 10^-8)^2 = 1.0 x 10^-15
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