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Stoicheometry Help !!?
Stoicheometry Help !!?
I tried solving the problems so many times and I cant get it right... Plz help!
2(N2)+3(O2)--------> 2(N2O3)
(a) How many moles of N2 are required to react completely with 1 mole of O2?
(b) How many moles of N2O3 are produced from the complete reaction of 1 mole of O2?
(c) How many moles of O2 are required to produce 8 moles of N2O3?
Thank you soo much in advance:)
1 Answer
- 9 years agoFavorite Answer
you use the ratio of 2mol of N2 per 3mol of O2
so thus:
(2N2)/3O2)*(1O2)= 2/3N2 are required to make 1 mole of O2
Again use the ratio for B:
Given: 1 mold of O2
Needed: Mol of N2O3
so----> (2N2O3/3O2) * 1mole of O2= (2/3)*1
answer=2/3mol of N2O3
B: same process
Given: 8mol N2O3
Need: Mol of O2
Ratio= (Need/given)= (3molO2/ 2mol O2)*8= (3/2)8= 3mol of O2 are required
Source(s): Molecular Biology student
