Math Help!! Please. Word Problems?

Anya H Hi!

Math Help!! Please. Word Problems?

2. Julie has several coins, all nickels and quarters, in her piggy bank. The total amount of money that she has is $15.65. If Julie has 13 more nickels than quarters, how many quarters does she have?

N = Nickel

Q = quarter

.05N + .25Q = $ 15.65 ← eq1

Eq1 x 100

Result → 5N + 25Q = 1565

N = Q + 13 ← eq2

Substitute eq2 in eq1

5(Q + 13) + 25Q = 1565

5Q + 65 + 25Q = 1565

30Q = 1565 – 65

30Q = 1500

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Quarter = 50 Pieces ◄ Ans

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From eq2

N = Q + 13

N = 50 + 13

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Nickel = 63 Pieces ◄ Ans

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3. The owner of the most amazing circus was counting the money from the day's ticket sales. He knew that a total of 522 tickets were sold. Adult tickets cost 15$ each and children's tickets cost 8$ each. If the total receipts for the day were $5086.00, how many of each kind of ticket were sold?

A = Adult Ticket

C = Children Ticket

Total Ticket Sold = 522

A + C = 522 ← eq1

A = 522 – C ← eq2

$15A + $8C = $5086 ← eq3

Substitute eq2 to eq3

15(522 – C) + 8C = 5086

7830 – 15C + 8C = 5086

7C = 2744

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Children = 392 Tickets ◄ Ans

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From eq2

A = 522 – C

A = 522 - 392

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Adult = 130 Tickets ◄ Ans

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4. For the County cheer leading competition there was 206 more tickets sold at the door than were sold in advance. The tickets sold at the door cost $10 and the tickets sold in advance cost $6. The total amount of sales for both types of tickets was $6828. How many each type of ticket was sold?

Total tickets sold = Door Sold (DS) + Advance Sold(AS)

DS = AS + 206 ← eq1

$10DS + $6AS = $ 6828 ← eq2

Substitute eq1 to eq2

10(AS + 206) + 6AS = 6828

10AS + 2060 + 6 AS = 6828

16AS = 6828 – 2060

16 AS = 4768

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Advance Sold = 298 tickets ◄ Ans

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Substitute AS to eq1

DS = AS + 206

DS = 298 + 206

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Door Sold = 504 tickets ◄ Ans

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5. Chasity bought 6 new movies and 2 used movies for $127.92. At the same prices, payton bought 3 new movies and 8 used movies for $133.89. Find the cost of buying a single used movie

Chasity

NM = New Movies

UM = Used Movie

6NM + 2UM = $ 127.92 ← eq1

Payton

3NM + 8UM = $ 133.89 ← eq2

In eq2 multiply by (-2)

Result → -6NM – 16UM = - 267.78 ← eq3

Eq3 add to eq1

Result → -14UM = -139.86

UM = -139.86 / -14

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Used Movie = $ 9.99 ◄ Ans

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6. Juan's catering company is setting for a big event that will host 764 people. When they set up the tables they need 2 forks for each child and 5 forks for each adult. If the Juan's company ordered at total of 2992 forks, how many adults and how many children will be attending the event?

Af = Adult forks

Cf = child forks

5A + 2C = 2992 ← eq1

A + C = 764 people ← eq2

A = 764 – C ← eq3

Siubstitute eq3 to eq1

5(764 – C) + 2C = 2992

3820 – 5C + 2C = 2992

3C = 828

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Children = 276 ◄ Ans

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Substitute C = eq3

A = 764 – C

A = 764 - 276

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Adult = 488

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Hope this helps

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God Bless

Lim♥E

You probably could have answered them all in the time it took you to type all of that.

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