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Fred
Fred asked in Computers & InternetProgramming & Design · 9 years ago

Is there an easier way to write this in c++?

I want to right an if statement that says "if i is equal to any of the punctuation marks," do whatever.

Is there an easier way than:

if (i=='.' || i=='!' || i=='?' etc.)

2 Answers

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  • Paul
    Lv 4
    9 years ago
    Favorite Answer

    There is an easier way.

    If you look at an ASCII table, you will notice all the punctuation symbols are between 33 and 47 where "!" is the 33rd character and "/" is the 47th character.

    So you can just check if the character is between 33 and 47.

    ie

    if (i >= '!' && i <= '/')

    {

    // i is punctuation

    }

    Source(s): http://www.asciitable.com/
  • SteveO
    Lv 7
    9 years ago

    No there is not, unless you want to use a switch block which wouldn't really be well suited if you're just testing if a punctuation mark is in some string. You could use a regular expression if you wanted.

    EDIT: Yeah, forgot about the ASCII table...I guess that's what happens when I'm tired. That is an excellent solution to this.

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