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Chemistry problems (before maintenance? :) )?
5. At 0 deg celcius under a pressure of 1000 mmHg, a given weight of N2 occupies a volume of 1 Liter. At -100 deg celcius the same weight of gas under the same pressure occupies a volume of .6313 Liter. Calculate the absolute zero in degrees centigrade (I don't really know absolute zero means)
Assuming that dry air contains 79% N2 and 21% O2 by volume, calculate the density of moist air at 25 deg. celsius and 1 atm pressure when the relative humidity is 60%. The vapor pressure of water at 25 deg celcius is 23.76 mmHg
At 27 deg. celcius, 500 cc of H2, measured under a pressure of 400 mmHg and 1000 cc of N2, measured under a pressure of 600 mmHg, are introduced into an evacuated 2-L flask. Calculate the resulting pressure ( I'm really lost here -_- )
1 Answer
- Roger the MoleLv 79 years agoFavorite Answer
In this instance "absolute zero" means the temperature at which this gas, treated as an ideal gas, would have a volume of zero. (Among other things, an ideal gas doesn't liquify or solidify and its molecules occupy no space.)
So this problem is essential one of proportions:
0°C = 1.000 L
-100°C = 0.6313 L
z = 0.0000 L
Find z.
(0 - (-100)) / (1.000 - 0.6313) = (0 - z) / (1.000 - 0)
solve for z algebraically:
z = -271.2°C
