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Write an equation of the line in slope intercept form that passes through the given points.?

Write an equation of the line in slope intercept form that passes through the given points. Please help me solve these two probs. Show work

•(1,4), (3,10)

•(2,5), (-2,8)

4 Answers

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  • 9 years ago
    Favorite Answer

    First find slope by using formula.

    (10-4)/(3-1)=6/2=3

    Slope intercept form is in the form y = mx+b

    where m is the slope and b is a constant

    So we need to plug our slope in.

    y = 3x + b

    We need to find b so we plug a point on that line in. Lets use the first point.

    4 = 3(1) + b

    b =1

    y = 3x + 1

    I solved the first problem now you can solve the next one by my work above.

  • 5 years ago

    slope intercept style: y=mx+b, the position m is the slope and b is the y intercept(the position the line crosses the y axis) so your situation elements each thing except b so positioned all that in to discover b: undergo in concepts, factors are written (x,y). -9= -5(3)+b multiply: -9= -15+b upload 15 to both aspect. you attempt to get b on one aspect and what you do to at least one aspect you should do to the different: 6=b. now you've b and m, so those are constants on your line. x and y replace because the criteria replace. very last equation: y= -5x+6 now, attempt the others: 8= -4(a million)+b 12=b so y= -4x+12 -2=a million/2(4)+b -2=2+b b=-4 so y=a million/2x-4

  • Anonymous
    9 years ago

    gradient m=y-y1/x-x1

    10-4/3-1=6/2=3

    y-y1=m(x-x1)

    y-4=3(x-1)

    y=3x-3+4

    y=3x+7

    gradient for the second is

    8-5/-2-2=3/-4

    y-5=3/-4(x-2)

    -4y+20=3x-6

    y=-3x/4+13/2

  • Steven
    Lv 7
    9 years ago

    first you need the slope

    rise over run

    y/x

    (y1-y2)/(x1-x2)

    either point can be 1

    either point can be 2

    whichever way is easier to subtract

    then subtract the values of the point from ther relative variable

    •(1,4), (3,10)

    (10-3)/(3-1)

    7/2

    slope=7/2

    so you start with y=7x/2

    subtract a point

    (y-4)=7(x-1)/2

    y-4=7x/2-7/2

    y=7x/2-7/2+8/2

    y=7x/2+1/2

    or

    y=7(x+1)/2

    •(2,5), (-2,8)

    slope

    (8-5)/(-2-2)

    3/-4

    -3/4

    so start with

    y= -3x/4

    subtract a point

    (y-5)= -3(x-2)/4

    y-5= -3x/4+6/4

    y= -3x/4+6/4+20/4

    y= -3x/4+26/4

    or

    y= -3x/4+13/4

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