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KillieTillIDie7
KillieTillIDie7 asked in Science & MathematicsMathematics · 9 years ago

Maths Gradient Question?

P has coordinates (a,a^2) and Q has coordinates (2b,4b^2). What is the gradient of PQ in its simplest form?

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  • Anonymous
    9 years ago
    Favorite Answer

    y2 - y1 / x2 - x1......(a,a^2)(2b,4b^2)

    4b^2 - a^2 / 2b - a

    (2b - a)(2b + a) / 2b- a

    Cancel out both 2b - a

    2b + a (or a + 2b in alphabetical order)

  • anordtug
    Lv 6
    9 years ago

    The gradient or the slope of the line PQ is (4b^2- a^2)/(2b-a)=4b+a

    Then the line can be given by the equation y=(4b+a)x+ c where c is a constant.

    as y(a)= a^2= (4b+a)a+c

    c=a^2-4ab+a^2= (a-b)^2

    The line can therefore be presented like this: y=(4b+a)x + (a-b)^2

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