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Calculus question...help, please?
Here's the question/problem...
(NOTE, the "e" is that slanted/lowercase one that's equal to like 2.71...etc.)
f (x, t) = te^(2xt)
...Find fx (x, t) and ft (x, t)
Show work. Fastest answer with correct answer gets best answer. Thank you!
Sorry, I messed up. The actual function was f (x, t) = te^-(2xt) ...there was a negative. My bad. Can you redo the work/answer? Greatly appreciated!! Thanks! And yes, this is via partial derivative.
1 Answer
- 9 years agoFavorite Answer
Assuming that fx means partial derivative with respect to x,
f (x, t) = te^(2xt)
fx = te^(2xt) *2t
fx = 2t^2 * e^(2xt_
ft = 1*e^(2xt) + e^(2xt)*2x
ft = (2x+1) * e^(2xt)
