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math question help please?
A rectangular garden is 10 feet by 4 feet. A gravel border with uniform width along the sides and 90 degrees corners surrounds the garden. The area of the gravel border is six times the area of the garden What is the perimeter of the outside of the gravel border? Please Show work.
1 Answer
- tcLv 78 years agoFavorite Answer
let x be the width of border
(10+2x)(4+2x) => the area of the garden and gravel border
(10+2x)(4+2x) - 40 => the area of the gravel border
(10+2x)(4+2x) - 40 = 6(10*4) = 240
solving
4x^2+28x-240 = 0
4(x-5)(x+12) = 0
x = 5
so,
2[(10 + 2x) + (4+2x)] = 68 ft.
