Write the slope-intercept form of the equation of the line through the given point?

Y= -5x-34

first, get the current equation into slope-intercept form and get Y= 1/5x-7.5

since the slope needs to be a negative reciprocal, flip the slope and negate it getting -5/1, which simplifies to -5.

to get the y-intercept, plug in the slope and the given point and solve for B:

Y=mx+b

(6)= -5(-8)+b

(6)= 40=b

-34=b

and then plug the y-intercept into the formula

Y= -5x-34

slope intercept form: y=mx+b, the position m is the slope and b is the y intercept(the position the line crosses the y axis) so your issue promises each little thing except b so positioned all that in to locate b: bear in mind, factors are written (x,y). -9= -5(3)+b multiply: -9= -15+b upload 15 to both aspect. you attempt to get b on one aspect and what you do to one aspect you should do to the different: 6=b. now you've b and m, so those are constants on your line. x and y replace because the criteria replace. very last equation: y= -5x+6 now, attempt the others: 8= -4(a million)+b 12=b so y= -4x+12 -2=a million/2(4)+b -2=2+b b=-4 so y=a million/2x-4