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A lead shot of mass 600g is heated to 100 C and placed in an aluminum can of mass 200g. Which contains 500g of?
A lead shot of mass 600g is heated to 100 C and placed in an aluminum can of mass 200g. Which contains 500g of water initially at 17.5 C. The specific heat of the aluminum can is 0.215 cal/g. The final temp of the mixture is 20 C. what is the specific heat of lead?
2 Answers
- electron1Lv 78 years agoFavorite Answer
Heat energy flows from the high temperature lead shot to the water and can, until the temperature of lead shot, water, and can is 20˚. Since the can contains 500g of water, the temperature of the can is the same as the water.
Heat energy released from the lead shot = Heat energy absorbed by the water and can
∆ Q = mass * Specific heat * ∆T
For the lead shot, ∆T = 100 – 20 = 80
∆ Q = 600 * Sp.ht. * 80
For the water and can, ∆T = 20 – 17.5 = 2.5
Specific heat of water = 1 cal/g* ˚C
For the water, ∆ Q = 500 * 1 * 2.5
For the can, ∆ Q = 200 * 0.215 * 2.5
600 * Sp.ht. * 80 = 500 * 1 * 2.5 + 200 * 0.215 * 2.5
