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IMMLIKECOOOL=] asked in Science & MathematicsMathematics · 8 years ago

Can anyone help me with algebra?

All you have to do is solve...

x/x+2 + 2/x-2 = x+6/x^2-4

PLEASE!

2 Answers

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  • ranjankar
    Lv 7
    8 years ago
    Favorite Answer

    ( x^2- 4) = ( x+2) ( x-2)

    LCM = (x+2) ( x-2)

    MULTIPLY BOTH SIDES BY LCM

    x ( x-2) + 2(x+2) = x+6

    x^2 -2x +2x +4 = x+6

    x^2 -x -2 = 0

    x^2 +x -2x -2 = 0

    x ( x+1) -2( x+1) = 0

    ( x-2) ( x+1) = 0

    x = 2 OR -1

    x cannot be 2 because in that case x-2= 0

    ANSWER x = -1

  • zxcv
    Lv 5
    8 years ago

    Multiply both sides by (x+2)*(x-2)=x^2 - 4 to get

    x*(x-2) + 2*(x+2) = x + 6

    x^2 - 2x + 2x + 4 = x + 6

    x^2 - x - 2 = 0

    x = -1 or x = 2, but x=2 is undefined in the original equation (because of the 2/x-2) so x=-1 only.

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